1 Answer

Talus · Answer 1 · 2022-01-29T23:23:51+0000

Answer:

122.5 ohm

Step-by-step explanation:

Given :

P=40 w

V= 70 V

R=?

Resistance can be calculated as :

$P=(V^(2) )/(R) \\40=((70)^(2) )/(R)\\40=(4900)/(R) \\R=(4900)/(40) \\R=122.5 ohm$

Therefore, resistance of the bulb will be 122.5 ohm

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