Question

At 1 atm, how many moles of co2 are released by raising the temperature of 1 liter of water from 20∘c to 25∘c?.

Answer 1

Answer is: 0,0030 mol of carbon dioxide.

Carbon dioxide solubility in water at 20°C and 1 atm is: 3,8·10⁻² mol/L.

Carbon dioxide solubility in water at 25°C and 1 atm is: 3,5·10⁻² mol/L.

Difference is: 0,038 mol/L - 0,035 mol/L = 0,003 mol/L.

V(carbon dioxide) = 1 L.

n(carbon dioxide) = V · c.

n(carbon dioxide) = 1 L · 0,003 mo/L.

n(carbon dioxide) = 0,0030 mol.