Question

Please i have 15 minutes​

Answer 1

`x = (-\log 7)/(\log 7 - \log 2)`

Explanation:

`2^x = 7^(x + 1)`

Take the log of both sides.

`\log 2^x = \log 7^(x + 1)`

Use properties of log.

`x \log 2 = (x + 1) \log 7`

`x \log 2 = x \log 7 + \log 7`

`x \log 2 - x \log 7 = \log 7`

`x(\log 2 - \log 7) = \log 7`

`x = (\log 7)/(\log 2 - \log 7)`

`x = (\log 7)/(-(\log 7 - \log 2))`

`x = (-\log 7)/(\log 7 - \log 2)`