Question

40 ohms

1.2 A
40 ohms
12 V


Calculate the total energy developed in 5
minutes by the system above.​

Answer 1

17280 J and 1080 J

Step-by-step explanation:

Given :

R= 40 ohm

I=1.2A

t= 5 min=60×5=300 sec

Now,

Total energy can be calculated as:

`E=I^(2) Rt\\E=(1.2)^(2) *40*300\\E=17280 J`

Now,

V=12V

R=40 Ohm

`E=(V^(2) )/(R) *t\\E=((12)^(2) )/(40) *300\\E=1080 J`

Total energy is 17280 J and 1080 J