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Use aâ t-test to test the claim about the population mean at the given level of significance using the given sample statistics. Assume the population is normally distributed.

Claim: μ>77; α=0.05
Sample statistics: xÌ =78.6,s=3.7,n=23

a. What are the null and alternative hypotheses?
b. What is the value of the standardized test statistic?
c. What is the P-value of the test statistic?

User Kmdreko
by
7.6k points

1 Answer

6 votes

Answer:

a) NULL Hypothesis


H_0:\mu \leq 77

ALTERNATIVE hypotheses


H_0: \mu>77

b) Therefore t Critical value from table X is


X=\pm 1.717

c) Hence,we reject the Null hypothesis

Explanation:

From the question we are told that:

Claim:


\mu=77

Level of significance
\alpha=0.05

Sample mean
\=x=78.6

Sample Standard deviation
\sigma=3.6

Sample size
n=23

a)

Generally the equation for The null and alternative hypotheses is mathematically given by

NULL Hypothesis


H_0:\mu \leq 77

ALTERNATIVE hypotheses


H_0: \mu>77

b)

Generally the equation for The standardized test statistics t is mathematically given by


t=((\=x-\mu))/((\sigma)/(√(n)))


t=((78.6-77))/((3.7)/(√(23)))


t=2.03

Therefore Critical Value X is


X=(\alpha,df)

Where


df=(23-1)\\\\df=22

Therefore t Critical value from table X is


X=\pm 1.717

c)

The Test statistics is outside the Critical Value

Hence,we reject the Null hypothesis

User Kumar Kundan
by
8.3k points
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