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Al lanzar un dado dos veces consecutivas. ¿Qué probabilidad hay de obtener primero un 3 y luego un numero par?

1 Answer

3 votes

Answer:

The probability is 1/12.

Explanation:

Number of elements in sample space is 6 . Even numbers are 2, 4 and 6 so the there are 3 three even numbers.

So, the probability of getting 3 on the first chance and then an even number in the second chance is


P = (1)/(6)* (3)/(6)\\\\P = (1)/(12)

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