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Suppose a jar contains 8 red marbles and 25 blue marbles. If you reach in the jar and pull out 2 marbles at random, find the probability that both are red.

1 Answer

4 votes

Answer:
(7)/(132)

Explanation:

Total marbles in the jar = 8+25 = 33

Using combinations, the number of ways of choosing two marbles out of 33=
(33!)/(2!(33-2)!)\\\\=(33!)/(2*31!)\\\\=(33*32)/(2)=528 (total outcomes)

Similarly, the number of ways of choosing two red marbles =


(8!)/(2!6!)\\\\=(8*7)/(2)=28(favorable outcomes)

Required probability =
\frac{\text{favorable outcomes}}{\text{total outcomes}}


=(28)/(528)\\\\=(7)/(132)

hence, required probability =
(7)/(132)

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