Question

Two particles, with identical positive charges and a separation of 2.65 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration 1 whose magnitude is 5.00 103 m/s2, while particle 2 has an acceleration 2 whose magnitude is 7.70 103 m/s2. Particle 1 has a mass of 6.20 10-6 kg. (a) Find the charge on each particle. q1 = C q2 = C (b) Find the mass of particle 2. kg

Answer 1

a)
`q=4.92*10^(-8) C`

b)
`m=4.026*10^(-6) kg`

Explanation:

From the question we are told that:

Separation distance
`d=2.65*10^(-2) m`

Acceleration 1
`a_1=5.00*10^3 m/s^2,`

Acceleration 2
`a_2=7.70*10^3 m/s^2,`

Mass 1
`m_1=6.20*10^(-6)`

Generally the equation for Force is mathematically given by

`F=ma`

For Particle 1

`F=6.2*10^(-6) *5*10^3`

`F=0.031 N`

Also

`F=(kq_1*q2)/(r^2)`

Where

`q_1=q_2`

Therefore

`0.031=(9*10^9*q^2)/((2.65*10^-2)^2)`

`q=4.92*10^(-8) C`

b)

Generally the equation for Force is mathematically given by

`F=ma`

`0.031=7.7*10^3`

`m=4.026*10^(-6) kg`