Question

A car accelerates along a straight road from rest to 90 km/h in 5.0 s. A) Find the magnitude of its average acceleration. B) Find the velocity of the car at t = 1.0 s, t = 2.0 s and t = 5.0

Answer 1

a)
`A=5m/s^2`

b)
`V=25m/s`

Step-by-step explanation:

From the question we are told that:

Velocity
`v=90km/h=25m/s`

Time
`t=5.0s`

a)

Generally From Newton's motion equation for Average acceleration is mathematically given by

`A=(V-U)/(t)`

Since its from Rest Therefore

`U=0`

`A=(25m/s-0)/(5s)`

`A=5m/s^2`

b)

Generally the equation for Average Velocity is mathematically given by

`V=u+at`

`AT t=1.0s\\\\V=0+5(1)`

`V=5m/s`

`AT t=2.0s\\\\V=0+5(2)`

`V=10m/s`

`AT t=5.0s\\\\V=0+5(5)`

`V=25m/s`