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(x^2-5)(x+3)+(x+4)(x-x^2)

2 Answers

4 votes

Answer:

-x-15

Explanation:

Expand using the FOIL Method.

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User AndreasW
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\implies {\blue {\boxed {\boxed {\purple {\sf {-(x+15)}}}}}}


\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}


\:( {x}^(2) - 5)(x + 3) + (x + 4)(x - {x}^(2) )


\: {x}^(2) (x + 3) - 5(x + 3) + x(x - {x}^(2) ) + 4(x - {x}^(2) )


\: {x}^(3) + 3 {x}^(2) - 5x - 15 + {x}^(2) - {x}^(3) + 4x - 4 {x}^(2)

Combining like terms, we have


\: {x}^(3) - {x}^(3) + 3 {x}^(2) + {x}^(2) - 4 {x}^(2) - 5x + 4x - 15


\: - x - 15


\: - (x + 15)


\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

User Oeuftete
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