Question

2㏒x-㏒[x-2]=2㏒3: solve the equation

Answer 1

Explanation:

`2 log(x) - log(x - 2) = 2 log(3)`

`log(x {}^(2) ) - log(x - 2) = log(9)`

`log( \frac{ {x}^(2) }{x - 2} ) = log(9)`

`\frac{ {x}^(2) }{x - 2} = 9`

`{x}^(2) = 9x - 18`

`{x}^(2) - 9x + 18 = 0`

`(x - 3)(x - 6) = 0`

`x = 3`

and

`x = 6`