Question

Solve the system of equations y=2x-3 and y=x^2-3

Answer 1

I have attached some answers in the photos below hope you find them useful

Answer 2

0 and 1

Explanation:

Given :

`y= 2x-3\\y=2x^(2) -3`

Now equate the both equation :

`2x-3=2x^(2) -3`

2x=2
`x^(2)`

x-
`x^(2)`=0

x(1-x)=0

x=0

1-x=0

x=1

Therefore, x=0,1