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2 votes
3

JK, KL, and IJ are all tangent to o (not drawn to scale). JA = 8, AL = 11, and
CK = 10. Find the perimeter of AJKL.

User Froxx
by
5.7k points

1 Answer

5 votes

Answer:


P = 58

Explanation:

The image if the circle and triangle can be found online

Given


JA = 8


AL = 8


CK = 10

Required

The perimeter of JKL

Since the mid-points of the tangents are A, B and C respectively.


JK = JB + BK

Where


JB = JA = 8


BK = CK = 10

So:


JK =8+10 =18


JL = JA + AL


JL = 8+11 = 19


KL = CL + CK

Where


CL =AL = 11

So:


KL = 11+10 = 21

So, the perimeter (P) is:


P = JK+ KL +JL


P = 18 + 19 + 21


P = 58

User Hafenkranich
by
5.7k points
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