Question

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What is the molarity of 150 g C6H12O6 per 0.50 L?

A. 300 mol/L
B. 75.0 mol/L
C. 1.68 mol/L
D. 0.833 mol/L

Answer 1

Answer: The correct option is C) 1.68 mol/L

Step-by-step explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

`\text{Molarity of solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}* \text{Volume of solution (L)}}` .....(1)

Given values:

Given mass of
`C_6H_(12)O_6` = 150 g

Molar mass of
`C_6H_(12)O_6` = 180 g/mol

Volume of the solution = 0.50 L

Putting values in equation 1, we get:

`\text{Molarity of solution}=(150)/(180* 0.50)\\\\\text{Molarity of solution}=1.68M`

Hence, the correct option is C) 1.68 mol/L