Question

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Suppose that 100 g of metal gained 110 cal of heat when the temperature is increased form 60°C to 70°C. What is the specific heat of metal?​

Answer 1

q=mcΔt

110=100.c.(70-60)

c=0.11

Answer 2

110 cal kg⁻¹°C⁻¹

Step-by-step explanation:

Formula to find the specific heat capacity is :

Q = m c Θ

Here,

Q = heat energy

m = mass

c = specific heat capacity

Θ = change in temperature

Now let us find the specific heat capacity now.

Q = m c Θ

110cal = 1kg × c × (70 - 60 ) °C

110cal= 0.1kg × c × 10°C

110 = 1 c

Divide both sides by 1.

c = 110 cal kg⁻¹°C⁻¹