Question

What happens if simultaneous Equations have two of the same variable like below? How would I solve it?

6A + 4B + 5C = 390
6A + 4B + 5.75C = 405​

Answer 1

C = 20

Explanation:

What happens if simultaneous Equations have two of the same variable like below? How would I solve it?

6A + 4B + 5C = 390

6A + 4B + 5.75C = 405​

Step 1

We solve for C first

6A + 4B + 5C = 390....Equation 1

6A + 4B + 5.75C = 405​... Equation 2

We substract Equation 1 from Equation 2

0.75C = 15

C = 15/0.75

C = 20