Question

Find the value of x in the isosceles triangle shown below.

Answer 1

Answer: C

Step-by-step explanation: We only need to find the value of one of the x so just use Pythagorean theorem but simplified to do it in one step which is sqrt(4^2+6^2) which gives us sqrt(52).

Answer 2

22.18 = x

Step-by-step explanation:

a^2 + (b)^2 = (x/2)^2

a = sqrt(74)

b = 7

x/2 = ?

(74)[^1/2]^2 = 74

b^2 = 7^2 = 49

74 + 49 = (x/2)^2 Substitute into a^2 + b^2 = c^2

123 = (x/2)^2 Combine like terms

(123^0.5) = x/2 Take the square root of both sides.

11.09 = x/2 Multiply both sides by 2

11.09*2 = x

22.18 = x The full length of the base of the triangle is 22.18