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{x}^(2) + 2x = 0


User Reukiodo
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Answer:


\textbf{Hello!}


\Longrightarrow2^2+2z=0


\Longrightarrow x_(1,\:2)=(-2\pm √(2^2-4\cdot \:1\cdot \:0))/(2\cdot \:1)


\Longrightarrow √(2^2-4\cdot \:1\cdot \:0)


\Longrightarrow =√(2^2-0)


\Longrightarrow =√(2^2)


\Longrightarrow=2


\Longrightarrow x_(1,\:2)=(-2\pm \:2)/(2\cdot \:1)


\Longrightarrow x_1=(-2+2)/(2\cdot \:1),\:x_2=(-2-2)/(2\cdot \:1)


\Longrightarrow(-2+2)/(2\cdot \:1)


\Longrightarrow =(0)/(2\cdot \:1)


\Longrightarrow =(0)/(2)


=0


\Longrightarrow(-2-2)/(2\cdot \:1)


\Longrightarrow =(-4)/(2\cdot \:1)


\Longrightarrow =(-4)/(2)


\Longrightarrow =-(4)/(2)


=-2


x=0,\:x=-2\Longleftarrow


\underline{HOPE ~IT~HELPS}

User Del Bao
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