Question

A certain first-order reaction is 27.5 percent complete in 8.90 min at 25°C. What is its rate constant?

Answer 1

`k= 0.145min^(-1)`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us remember that the first-order kinetics is given by:

`ln(A/A_0)=-kt`

Whereas the 27.5% complete means A/Ao=0.275, and thus, we solve for the rate constant as follows:

`k=(ln(A/A_0))/(-t)`

Then, we plug in the variables to obtain:

`k=(ln(0.275))/(-8.90min)\\\\k= 0.145min^(-1)`

Regards!