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Complete the square to rewrite y=x2 - 6x + 2 in vertex form. Then state whether the vertex is a maximum or a minimum and give its coordinates.

A. Maximum at (-3, -7)

B. Maximum at (3,-7)

C. Minimum at (3, -7)

D. Minimum at (-3, -7) ​

2 Answers

5 votes

Answer:

C) Minimum at (3,-7)

Explanation:


y=x^2-6x+2


0=x^2-6x+2


0+7=x^2-6x+2+7


7=x^2-6x+9


7=(x-3)^2


0=(x-3)^2-7


y=(x-3)^2-7

Because the parabola opens upward, the vertex is the minimum of the function. Therefore, the vertex is the minimum at (3,-7).

User Donnette
by
3.7k points
1 vote

Answer:

C is the Answer

Explanation:

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User Matelutex
by
3.7k points