Question

`\int _(2.2)^(+\infty \:)(10.648)/(x^2)`

Answer 1

Explanation:

`\int _(2.2)^(+\infty \:)(10.648)/(x^2)dx = 10.648 \int _(2.2)^(\infty \:)(dx)/(x^2)`

`= - (10.648)/(x) | _(2.2)^( \infty) = 4.84`