Question

Calculate the work function that requires a 455 nm photon to eject an electron of a value 0.73 eV

Answer 1

W = 2 eV

Step-by-step explanation:

Given that,

The wavelength of a photon = 455 nm

The kinetic energy of a photon, K = 0.73 eV

We need to find the work function of the electron. It can be solved using Einstein's equation such that,

`W=E-K`

E is the energy of the photon

So,

`W=(hc)/(\lambda)-K\\\\W=(6.63* 10^(-34)* 3* 10^8)/(455* 10^(-9)* 1.6* 10^(-19))-0.73\\\\W= 2.73\ eV-0.73\ eV\\\\W=2\ eV`

So, the work function of the metal is 2 eV.