Question

The first practical car to use a gasoline engine was built in London in 1826. The power generated by the engine was just 2.984 KW. How long would this engine have to run to produce 3.60 × 104 J of work?

Answer 1

To calculate the time it would take for an engine with a power output of 2.984 kW to do 3.60 × 104J of work, use the formula t = W / P. The result is approximately 12.057 seconds.

Step-by-step explanation:

The student's question deals with the amount of time it would take for an engine with a power output of 2.984 kW to do 3.60 × 104J of work. Work (W) is related to power (P) and time (t) by the equation W = P × t. To find the time, we rearrange the equation to t = W / P. Plugging in the values from the question, we get t = (3.60 × 104J) / (2.984 kW), noting that 1 kW = 1000 J/s, so we convert the power to 2.984 × 1000 J/s. The calculation becomes t = (3.60 × 104J) / (2.984 × 1000 J/s), which gives us the time in seconds. Carrying out this division, we find the time t required is approximately 12.057 seconds to produce the work mentioned.