Question

the grade point average collected from a random sample of 150 students. assume that the population standard deviation is 0.78. find the margin of error if c = 0.98.

Answer 1

`E = 14.81\%`

Step-by-step explanation:

Given

`n = 150`

`\sigma = 0.78`

`c = 0.98`

Required

The margin of error (E)

This is calculated as:

`E = z * (\sigma)/(√(n))`

When confidence level = 0.98 i.e. 98%

The z score is: 2.326

So, we have:

`E = 2.326 * (0.78)/(√(150))`

`E = 2.326 * (0.78)/(12.247)`

`E = (2.326 *0.78)/(12.247)`

`E = (1.81428)/(12.247)`

`E = 0.1481`

Express as percentage

`E = 14.81\%`