Question

If O is an angle in standard position and its terminal side passes through the point

(8,-7), find the exact value of csc 0 in simplest radical form.

Answer 1

Explanation:

Let first find the x and y xomponets.

X componets is 8 and the y componets is -7 so

`r = \sqrt{ {x}^(2) + {y}^(2) }`

`r = √( 64 + 49)`

`r = √(113)`

`\csc(x) = (r)/(y)`

So

`\csc(x) = - ( √(113) )/( 7)`