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what is an equation in standard form of an ellipse centered at the origin with vertex (-4,0) and co-vertex (0,5)???

1 Answer

5 votes

Answer:


(x^2)/(16)+(y^2)/(25)=1

Explanation:

The equation of an ellipse with a center at
(h, k) and vertices at
(h\pm a, k) and
(h, k\pm b) is given by
((x-h)^2)/(a^2)+((y-k)^2)/(b^2)=1.

Since two vertices are located at (-4, 0) and (0, 5), the other vertices must be located at (4, 0) and (0, -5).

What we know:

  • Center of (0, 0)
  • From
    (h\pm a, k),
    a must be 4
  • From
    (h, k\pm b),
    b must be 5

Thus, we have:


((x-0)^2)/(4^2)+((y-0)^2)/(5^2)=1\implies \boxed{(x^2)/(16)+(y^2)/(25)=1}

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