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Find the equation (in terms of x ) of the line through the points (-2,5) and (3,4)
y=

User Carrier
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1 Answer

1 vote

Hi there!

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I believe your answer is:


y=-(1)/(5)x+(23)/(5)

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Here’s why:

  • We first need to find the slope of the equation.

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\boxed{\text{\underline{Slope Is...}}}\\\\\rightarrow(y_2-y_1)/(x_2-x_1)\\\\\boxed{\text{Key:}}\\\\\rightarrow (x_1,y_1)\text{ and }(x_2,y_2) - \text{Two Points Given}

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\boxed{\text{Calculating the Slope...}}\\\\\rightarrow m=(4-5)/(3-(-2))\\\\\rightarrow m=(-1)/(5)\\\\\rightarrow \boxed{m=-(1)/(5)}\\\\\\\text{The slope is } -(1)/(5).

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  • We then need to find the y-intercept of the equation.

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\boxed{\text{Calculating the intercept...}}\\\\y=-(1)/(5)x+b\\-------------\\\rightarrow 4 = -(1)/(5)(3) +b\\\\\rightarrow4= -(3)/(5)+b\\\\\rightarrow4+(3)/(5)= -(3)/(5)+(3)/(5) +b\\\\\rightarrow \boxed{(23)/(5)=b}

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\text{The equation should be: }\boxed{ y=-(1)/(5)x+(23)/(5) }.

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Hope this helps you. I apologize if it’s incorrect.

User Amitchhajer
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6.0k points