Question

(2sin60°)(3tan60°)—(4tan45°)(2cos45°)​

Answer 1

`9 - 4√(2)`

Explanation:

sin60° =
`(√(3) )/(2)`

tan60° =
`√(3)`

tan45° = 1

cos45° =
`(1)/(√(2) )`

(2sin60°)(3tan60°) - (4tan45°)(2cos45°)

now substitute the values of each trigonometrical angles

`(2*(√(3) )/(2) )(3*√(3) ) - (4*1)(2*(1)/(√(2) ) )`

`√(3) * (3√(3)) - 4*((2)/(√(2) ) )`

`3*3 - 4*(2)/(√(2) ) *(√(2) )/(√(2) )`

`9 - 4 *(2√(2) )/(2)`

`9 - 4 * √(2)`

`9 - 4√(2)`