Question

Show that ab =2redecele 10​

Answer 1

Explanation:

1)

`AB^2 = BD^2 + AD^2\\` ------- ( 1 )

`= 4^2 + (2\sqrt6)^2\\\\=16 + (4 * 6)\\\\= 16 + 24\\\\= 40`

`AB = \sqrt {40} = \sqrt {4 * 10} = 2√(10)`

2)

`AC^2 = AD^2 + DC^2` --------------( 2 )

`=(2 \sqrt6)^2 + 6^2 \\\\= 24 + 36\\\\=60`

`AC= √(60) = √(4 * 15) = 2 √(15)`

3)

BC² = AB² + AC²

(4 + 6)² = 40 + 60

100 = 100

Satisfies Pythagoras Theorem, therefore triangle ABC is right angles triangle.