Question

A crate is released from the highest point of a 12 m long ramp inclined at 60° with the horizontal. The motion is frictionless. What is the speed of the crate at the base of the ramp?​

Answer 1

law of conservation of mechanical energy

PE1 = Ek2

mgh=1/2mv²

h = 12 sin 60

`\tt v=√(2gh)=√(2* 9.8* 12* sin~60)=14.27~m/s`