Question

Nathaniel has $2 worth of dimes and quarters. He has 6 more dimes than quarters. By following the steps below, determine the number of dimes,x, and the number of quarters,y, that Nathaniel has.

Determine three ways to have 6 more dimes than quarters:

Answer 1

• 10 dimes and 4 quarters

Explanation:

• Number of dimes = d, each d = 10 c
• Number of quarters = q, each q = 25 c
• Total = $2 = 200 c

Equations according the given:

• 10d + 25q = 200
• d = q + 6

Solve for q by substitution:

• 10(q + 6) + 25q = 200
• 10q + 60 + 25q = 200
• 35q = 140
• q = 140/35
• q = 4

Find the value of d:

• d = 4 + 6 = 10

Nathaniel has 10 dimes and 4 quarters