Question

`3x { }^(2) + 8x + 4 \\`
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Answer 1

(x + 2)(3x + 2)

Explanation:

3x^2 + 8x +4

using middle term break method

so we need two numbers that gives 12 when multiplied and 8 when added.

6 and 2 are the numbers becoz 6*2 =12 and 6+2 =8

3x^2 + (6+2)x +4

multiply the brackets

3x^2 + 6x +2x 4

take commmon

3x(x + 2) +2(x + 2)

take x+2 as common

(x + 2)(3x*1 + 2*1)

(x + 2)(3x +2)