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1 vote
A system engine generating 5 hp is raising a load weighting 2000 lb. How high will the load be raised in 10s?

User Eatonphil
by
8.7k points

1 Answer

4 votes

Answer:

h = 44.5 m

Step-by-step explanation:

Given that,

Power of the engine, P = 5 hP = 3728.5 W

Weight of the load, W = 2000 lb = 8900 kg

We need to find how high the load be raised in 10 s.

We know that,

Power,
P=(W)/(t)

Where

W is work done

Also,

1 Pound = 4.45 newtons earth (N)


P=(F* h)/(t)\\\\h=(Pt)/(F)\\\\h=(8900* 10)/(2000)\\\\h=44.5\ m

So, the height raised by the load is 44.5 m.

User Dan Tanner
by
8.1k points
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