Answer:
![[H^+]=[OH^-]=1.0x10^(-7)M](https://img.qammunity.org/2022/formulas/chemistry/college/dly4r3blcrkxkzxkgs46k8krbjl2kk6gx2.png)
Step-by-step explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the relative concentrations by using the following equations:
![pH+pOH=14\\\\pH=-log([H^+])\\\\pOH=-log([OH^-])](https://img.qammunity.org/2022/formulas/chemistry/college/yqbc5w6ejwihcpvtzupvfa5ha8vo4hprde.png)
Thus, we realize that both pH and pOH are the same, 7, so that the concentration of H⁺ and OH⁻ are virtually the same, and can be calculated as follows:
![[H^+]=[OH^-]=10^(-7)=1.0x10^(-7)M](https://img.qammunity.org/2022/formulas/chemistry/college/1k9xyeraeb1x7nsri0cvuhsk8spdp731b2.png)
Regards!