Question

Find the equation for the line with

the given properties
perpendiculor to the line 7x-5y=9
containing the point (-2,-1)

Answer 1

y = -0.14286x + 1.2857

Explanation:

Don't really know how to explain over a computer, but it is correct. Answer from Omnicalculator.

Hope that this helps!

Answer 2

9514 1404 393

Answer:

5x -7y = -3

Explanation:

The equation of the perpendicular line can be written using the given equation as a starting point. Swap the x- and y-coefficients and negate one of them. In standard form, the x-coefficient must be positive.

Find the new constant by using the x- and y-values of the given point.

-7x -5y = 9 . . . . given equation

-5x -7y = c . . . . equation with coefficients swapped

5x -7y = c . . . . . equation with swapped coefficients, x-coefficient negated

5x -7y = c = 5(-2) -7(-1) = -10 +7 = -3

The equation of the perpendicular line is ...

5x -7y = -3