The question is incomplete, the complete question is;
A certain liquid X has a normal freezing point of 5.40 °C and a freezing point depression constant K=3.05 ?kg mol solution made of 46.1g of alanine (C3H,NO2) dissolved in 750. g of i. Round your answer to 3 significant digits.
Answer:
3.3 °C
Step-by-step explanation:
If ∆T= K m I
Where;
∆T = freezing point depression
K = freezing point constant
m= morality of solution
i= Van't Hoff factor
Number of moles of solute = 46.1 g/89.09 g/mol = 0.52 moles
Molality of solution = 0.52 moles /750 ×10-3Kg
= 0.69 m
∆T= 3.05 × 0.69 × 1
∆T= 2.10 °C
Freezing point of solution the solution = freezing point of pure solvent - freezing point depression
= 5.40°C - 2.10 °C
= 3.3 °C