Question

Factor this trinomial completely. 2x2 + 6x + 4 O

A. 2(x-2)(x + 1)

B. 2(x + 2)(x+1)

c. 2(x + 2)(x-1)

D. 2(x-2)(x - 1)​

Answer 1

`\sf\purple{B. \:2(x + 2)(x+1) }`

`\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}`

`2 {x}^(2) + 6x + 4`

Taking 2 as common factor, we have

`= 2 \: ( {x}^(2) + 3x + 2) \\ =2 \: ( {x}^(2) + 2x + x + 2)`

Taking
`x` as common from first two terms and 1 from last two terms, we have

`= 2 \:[x(x + 2) + 1(x + 2)]`

Taking the factor
`(x+2)` as common,

`= 2(x + 2)(x + 1)`

`\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}`

Answer 2

B. 2(x+2)(x+1)

Explanation: