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Use the grouping method to factor the polynomial below completely X3 - 3x2 + 5x - 15

A. (x2 - 5)(x+3)

B. (x2 - 3)(x + 5)

C. (x2 + 3)(x - 5)

D. (x2 + 5)(x - 3) ​

User JozeRi
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2 Answers

4 votes
D because d is the most appropriate answer
User Sabarish
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\longrightarrow{\green{D.\:(x²+5)(x-3)}}


\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}


{x}^(3) - 3 {x}^(2) + 5x - 15

Taking
x² as common from first two terms and 5 from last two terms, we have


➝ \: {x}^(2) \: (x - 3) + 5 \: (x - 3)

Taking the factor
(x-3) as common,


➝ \: ( {x}^(2) + 5)(x - 3)


\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

User Tal
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