88.8k views
0 votes
Could you show me how to do this?

Could you show me how to do this?-example-1
User Weienw
by
4.0k points

1 Answer

7 votes

9514 1404 393

Answer:

b ≈ 0.240450937397

Explanation:

To find the y-intercept of the tangent line, you need to know ...

a) the value of y at x=3

b) the slope of the curve at x=3

__

The slope is found by differentiating the function.

y = ln(x·e^(cos(x)²)) = ln(x) +cos(x)²

Then the derivative is ...

y' = 1/x +2(-sin(x)·cos(x)) = 1/x -sin(2x)

The y-intercept is ...

b = y - x·y'

b = ln(3) +cos(3)² -3(1/3 -sin(6))

The y-intercept is ...

b = ln(3) +3·sin(6) +cos(3)² -1 ≈ 0.240450937397

Could you show me how to do this?-example-1
User Bolat Tleubayev
by
4.0k points