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find the absolute maximum and the absolute minimum of the given function on the given interval f(x)=xe^x/2 on [-3,1]

User Downwitch
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1 vote

Answer:

Explanation:


f(x)=xe^{(x)/(2) } \\f'(x)=x*(1)/(2) e^{(x)/(2) } +e^{(x)/(2) } =e^{(x)/(2) } ((x)/(2) +1)\\

f'(x)=0, gives x=-2

we find f(x) at x=-3,-2,1

f(-3)=-3e^(-3/2)≈-0.67

f(-2)=-2e^(-2/2)=-2e^{-1}=-2/e≈-0.74

f(1)=1 e^(1/2)=√e≈1.65

User Jamie Barker
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2 votes

Answer:

View the graph for a visual

Explanation:

find the absolute maximum and the absolute minimum of the given function on the given-example-1
User Fegoulart
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