Question

(a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of 7.0 g. Silver has 47 electrons per atom, and its molar mass is 107.87 g/mol.

Answer 1

Answer: The number of electrons in given amount of silver are
`1.839* 10^(24)`

Step-by-step explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

......(1)

We are given:

Mass of silver = 7.0 g

Molar mass of silver = 107.87 g/mol

Putting values in equation 1:

`\text{Moles of silver}=(7.0g)/(107.87g/mol)=0.0650 mol`

According to the mole concept:

1 mole of a compound contains
`6.022* 10^(23)` number of particles.

Number of electrons per atom of silver = 47

So, 0.065 moles of silver will contain =
`(0.065* 6.022* 10^(23)* 47)=1.839* 10^(24)` number of electrons

Hence, the number of electrons in given amount of silver are
`1.839* 10^(24)`