102k views
0 votes
Find the equation of the straight line passing through the point (0,5)

which is perpendicular to the line
y = 5 x + 2​

User Snapfla
by
8.4k points

2 Answers

6 votes

Answer:

y = -x/5 + 5

Explanation:

Equation of a line L : y=mx+b perpendicular to another line L1 through a point P(p,q)

Given :

L1 : y = 5x+2

P : P(p,q) = P(0,5)

Solution :

Slope of L1 = 5. For L to be perpendicular, product of slopes = -1 =>

m*5=-1, or m = -1/5

Since L passes through P(0,5), using the point slope form of the line L :

L : (y-5) = -(x – 0) / 5

L : y = -x/5 + 5

User Vadik
by
8.3k points
4 votes

Answer:

y = -
(1)/(5) x + 5

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x + 2 ← is in slope- intercept form

with slope m = 5

Given a line with slope m then the slope of the line perpendicular to it is


m_(perpendicular) = -
(1)/(m) = -
(1)/(5)

The line crosses the y- axis at (0, 5 ) ⇒ c = 5

y = -
(1)/(5) x + 5 ← equation of perpendicular line

User James Close
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories