Answer:
Don't know if you meant to write 3t²i - 2tj
If so
a=dv/dt = 6ti - 2j
at t=1sec
a = 6(1)I - 2j
a=6i - 2j
Magnitude of a = √6²+(-2)²
a= 2√10ms-²
or 6.32ms-².
Velocity of a particle varies with its displacement as v = ( √(9 ... Velocity of a particle varies with its displacement as v = ( √(9 - x^2) ) m/sFind the magnitude of maximum acceleration of the particle.
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