Question

a right triangle has legs of lengths 7 and 2, what is the length of the hypotenuse to the nearest tenth

Answer 1

7.3

Explanation:

`7^(2) + 2^(2) = x^(2) \\ 53 = x^(2)\\√(53) = \sqrt{x^(2)} \\x = 7.3`

Answer 2

hypotenuse = 7.3

Explanation:

here 7 and 2 are the legs og the right triangle .we should find hypotenuse.

let the legs of the right triangle be a nd b respectively . And c be hypotenuse

using pythagoras theorem to find hypotenuse

a^2 + b^2 = c^2

7^2 + 2^2 = c^2

49 + 4 = c^2

53 = c^2

`√(53)` = c

7.28 = c

7.3 =c