Question

NO LINKS OR ELSE YOU'LL BE REPORTED! Only answer if you're very good at math.No guessing please.

A student is standing 20 feet away from the base of a tree.He looks to the top of the tree at a 50° angle of elevation.His eyes are 5 feet above the ground.Using cos 50=0.64,what is the height of the tree to the nearest foot?

A: 24 feet

B: 36 feet

C: 29 feet

D: 31 feet​

Answer 1

29 feet

Step-by-step explanation:

Solving this question above, we using Trigonometric function tangent = Opposite/Adjacent

Opposite side + h = Height of the tree

We are told that:

A student is standing 20 feet away from the base of a tree. He looks to the top of the tree at a 50 degree angle of elevation. His eyes are 5 feet above the ground.

20 feet = Adjacent side = Distance form the tree

tan 50 = (h+5)/20

Cross Multiply

h + 5 = 20 × tan50

h = 20tan50 - 5

h= 23.835071852

h =23.84

Therefore the height of the tree is calculated as:

23.84+5 feet

=28.84 feet

Answer 2

answer: 24ft
Step-by-step explanation:
SOHCAHTOA
cos = A/H
cos 50 = 20/H
20/H = .64
20 = .64 x H
20 / .64 = H
20 / .64 = 31.25 = H
pythagorean theorem
a^2 + b^2 = c^2
20^2 + b^2 = 31.25^2
400 + b^2 = 976.5625
976.5625 - 400 = b^2
576.5625 = b^2
square root 576.5625 = 24.0117
rounded to nearest whole number is 24