Find the sum (6a)/(a^(2)-6a+9)+(9)/(a^(2)-2a-3)

asked Jan 7, 2023 193k views

4 votes

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Answer:

Explanation:

$(6a)/(a^2-6a+9)}+(9)/(a^2-2a-3))\\\\=(6a)/((a-3)^2)+(9)/((a-3)(a+1))\\\\\\$

$=(6a(a+1)+9(a-3))/((a-3)^2(a+1))\\\\=(6a^2+6a+9a-27)/((a-3)^2(a+1))\\$

$=(6a^2+15a-27)/((a-3)^2(a+1))\\\\=(3(2a^2+5a-9))/((a-3)^2(a+1))$

Yunxia answered Jan 11, 2023

5.9k points

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