Question

A velocity selector consists of a uniform electric field of 3.4*10^6 V/m and a uniform magnetic field of 42.0 mT, perpendicular to each other, through which a beam of muons is fired (muons are a particle with 207 times the mass and the same charge as an electron). If the muons travel in a straight line, then what must be their velocity

Answer 1

The velocity of muons is
`8.1* 10^(7)m/s`.

Step-by-step explanation:

Electric field, E =
`3.4* 10^(6) V/m`

Magnetic field, B = 42 mT = 0.042 T

mass, m =207 x mass of electron

charge, q =
`1.6* 10^(-19)C`

Let the velocity is v.

The magnetic force on the charge is balanced by the electric force.

q v B sin 90 = q E

v x B = E

v x 0.042 =
`3.4* 10^6`

v =
`8.1* 10^(7)m/s`