Question

Solve for X. I really need help with problem. Please

Answer 1

Explanation:

I hope you can understand it

Answer 2

`\huge\bold{Given:}`

Angle AOB = x + 4

Angle BOC = 3x + 2

Angle AOC =90° ( ∵ it is right angle )

`\huge\bold{To\:find:}`

The value of "x".

`\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}`

`\longrightarrow{\blue{x\:=\:21°}}`

`\large\mathfrak{{\pmb{\underline{\purple{Step-by-step\:explanation}}{\purple{:}}}}}`

Since it is right-angle,

`Sum \: of \: angles \: = 90°`

`\longrightarrow{\green{}}` x + 4 + 3x + 2 = 90°

`\longrightarrow{\green{}}` x + 3x + 4 + 2 = 90°

`\longrightarrow{\green{}}` 4x + 6 = 90°

`\longrightarrow{\green{}}` 4x = 90° - 6

`\longrightarrow{\green{}}` 4x = 84°

`\longrightarrow{\green{}}` x =
`(84°)/(4)`

`\longrightarrow{\green{}}` x = 21°

`\sf\blue{Therefore,\:the\:value\:of\:x\:is\:21°.}`

Now, the two angles are

∠ AOB = x + 4 = 21° + 4 = 25°

∠ BOC = 3x + 2 = 3 x 21° + 2 = 63° + 2 = 65°

`\huge\bold{To\:verify :}`

➡ ∠ AOB + ∠ BOC = ∠ AOC

➡ 25° + 65° = 90°

➡ 90° = 90°

➡ L. H . S. = R. H. S

Hence verified. ✔

(Note:- Kindly refer to the attached file.)

`\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}`