Question

Determine the magnitude of the electrostatic force on a 0.06000 C charged object when it is placed in an electric field of magnitude 1500 N/C

Answer 1

Step-by-step explanation:

Use the following equation:

`E=(q)/(F)` and solve for F:

`F=(q)/(E)` and filling in:

`F=(.0600)/(1500)`

F = 4.0 ×
`10^{-4` N