Answer:
-11.13 Degree Celsius
Step-by-step explanation:
Here
Kf for H20 is 1.86 C/m
Mass of ethylene glycol = 27.1/100 * 100 = 27.1 grams
Number of moles of ethylene in 30 grams of ethylene = 27.1 g/molar mass of ethylene glycol = 27.1/62.07 = 0.4366 mol
Mass of water = 100 – 27.1 = 72.9 grams
Molality = Moles/Mass of water in Kg = 0.4366 /0.0729 = 5.989 m
Melting Point Depression = Kf * Molality = 1.86 *5.989 = 11.13 deg C
Melting point of solution = Melting point of water - Melting Point Depression
= 0 – 11.13 = -11.13 Degree Celsius